For many years, organized crime ran a numbers game that is now run legally by many state governments. the player selects a three digit number from 000 to 999. there are 1000 such numbers. a bet of $1 is placed on a number, say number 115. if the number is selected, the player wins $500. if any other number is selected, the player wins nothing. find the expected value for this game and describe what it means
1.3 x 10^-4 * n = <span>2.6 x 10^12
n = </span>2.6 x 10^12 / 1.3 x 10^-4
n = (2.6 / 1.3) x 10^16
n = 2 x 10^16
Answer
Idle the value of n = 2 x 10^16
There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula
(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4
(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A
Answer:
Im going to guess that this is a true or false question so..
True :)
Answer:
D 1.33
Step-by-step explanation:
B and C are less than 1
A is one and .30
D is one and .33
33>30