Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
C
because you just eliminate it
Answer:
y = -5/4x - 4
Step-by-step explanation:
Plug in 6 for y and -8 for x. Then solve for b or "y-intercept". You should get -4
It is 100. There is many ways to find this answer. One way would be to divide 1000 by 10 to get a 100. Another way is to take the decimal form of 1/10 which is .10 and times it by 1000 to get 100.
Step-by-step explanation:
0 is right in the middle of all negative and all positive numbers.
0 is therefore larger than any negative number and smaller than any positive number.
and 0×n = 0, always, no matter what n is.
-0 = +0 = 0.
so, of course, only
4.1m > -16.4
is correct.
0 is not greater than 16.4.
0 is not smaller than -16.4.
