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ASHA 777 [7]
4 years ago
15

RIDDLE ME THIS Fresh and invigorated after completing her algebra homework, Mimi appeared at the living room door. She held a pi

ece of paper covered in scribbled numbers, 'm's, 'd's, and equations. "Dad!" she announced. "Five years from now you'll be only double my age!" "Amazing!" Dad almost looked up from the TV, but knew she hadn't finished. "But five years ago, you were triple my age then!" "I suppose in another ten years we'll be the same age," Dad grunted, changing channels. How old is Mimi? Hint Don't pay any attention to Dad's rather mindless comment at the end! He'd had a tough day.
Mathematics
1 answer:
Marat540 [252]4 years ago
8 0

Answer:

Mimi is 15.

Step-by-step explanation:

Set up two equations, and solve by elimination.

 2(m+5) = d+5

- 3(m-5) =  d-5

_____________

2(m+5) - 3(m-5) = 10

2m + 10 - 3m + 15 = 10

-m + 25 = 10

-m = -15

<u>m = 15</u>

Plug this back in to get dad's age.

2(m+5) = d+5

2(15+5) = d + 5

2(20) = d + 5

40 = d + 5

<u>d = 35</u>

<u></u>

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Represent each of the following integers on the number line -4,3, -1,10,-8 and -15​
MArishka [77]

Answer:

-15, -8, -4, -1, 3, 10

Step-by-step explanation:

On the number line, the integers would be set up as :-

-15, -8, -4, -1, 3, 10

Hope this helps, thank you :) !!

5 0
3 years ago
Twenty-nine billion,thirty-two million in standard form
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The answer is 29,032,000,000
5 0
3 years ago
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In a company there are 33 male and 42 female staff. Calculate the percentage of male and female staffs
VMariaS [17]

Answer: 44%, 56%

Step-by-step explanation:

Given

A company has 33 males and 42 female staff

So, the total staff is the sum of male and female

\Rightarrow \text{Total=}33+42\\\Rightarrow \text{Total=}75

The percentage of male staff is

\Rightarrow \text{Male }\%=\dfrac{33}{75}\times 100\\\\\Rightarrow  \text{Male }\%=44\%

The percentage of female staff is

\Rightarrow \text{female }\%=\dfrac{42}{75}\times 100\\\\\Rightarrow  \text{female }\%=56\%

7 0
2 years ago
2) In order to receive a passing grade in your math class, you must attain an average of at least 65. If your scores on 5 exams
Xelga [282]

Answer:

73

Step-by-step explanation:

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7 0
3 years ago
Find the fifth roots of 243(cos 260° + i sin 260°).
Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5)  where k=0,1,2,3,4


So the first root of 243 (cos 260° + i sin 260°)  

is z1 =  243^1/5 ( cis ( 260 + 360 *0)/5)  

          3 cis ( 260/5)

        = 3 cis (52)

        = 3 cos (52 + i sin 52)


The second root of  243 (cos 260° + i sin 260°)  

is z2 =  243^1/5 ( cis ( 260 + 360 *1)/5)  

          3 cis ( 620/5)

        = 3 cis (124)

        = 3 cos (124 + i sin 124)


The third root of  243 (cos 260° + i sin 260°)  

is z3 =  243^1/5 ( cis ( 260 + 360 *2)/5)  

          3 cis ( 980/5)

        = 3 cis (196)

        = 3 cos (196 + i sin 196)


The fourth root of  243 (cos 260° + i sin 260°)  

is z4 =  243^1/5 ( cis ( 260 + 360 *3)/5)  

          3 cis ( 1340/5)

        = 3 cis (268)

        = 3 cos (268 + i sin 268)


The fifth root of  243 (cos 260° + i sin 260°)  

is z5 =  243^1/5 ( cis ( 260 + 360 *4)/5)  

          3 cis ( 1700/5)

        = 3 cis (340)

        = 3 cos (340 + i sin 340)

6 0
3 years ago
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