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AnnyKZ [126]
3 years ago
7

Can anyone help me do this?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

answer explained in the photo.

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There are 10 marbles in a bag 7 of them are blue and the rest are green If I randomly picked a marble from the bag what is the p
igomit [66]

Answer:

7/10

Step-by-step explanation:

10 marbles in a bag 7 of them are blue and the (10-7)=3 green

P( blue) = blue / total

            = 7/10

7 0
3 years ago
Match each set of points with the slope of the line formed by the ordered pairs.
Fynjy0 [20]

1) The slope of the point (0,0) and (2,1) is 1/2.

2) The slope of the point (0,-1) and (2,-5) is -2.

3) The slope of the point (0,7) and (2,4) is -3/2.

4) The points (-1,3) and (-1,-3) has No slope.

5) The slope of the point (1,-3) and (-1,-3) is zero.

<u>Step-by-step explanation:</u>

There are five set of points given in the question.

You need to find out the slope of the line formed by the points.

The formula used to find the slope of a line is given by,

Slope = \frac{y2-y1}{x2-x1}

1) The given points are (0,0) and (2,1)

(x1,y1) ⇒ (0,0)

(x2,y2) ⇒ (2,1)

Slope = \frac{1-0}{2-0}

⇒ 1/2 is the slope.

2) The given points are (0,-1) and (2,-5)

(x1,y1) ⇒ (0,-1)

(x2,y2) ⇒ (2,-5)

Slope = \frac{-5+1}{2-0}

⇒ \frac{-4}{2}

⇒ -2 is the slope.

3) The given points are (0,7) and (2,4)

(x1,y1) ⇒ (0,7)

(x2,y2) ⇒ (2,4)

Slope = \frac{4-7}{2-0}

⇒ -3/2 is the slope.

4) The given points are (-1,3) and (-1,-3)

(x1,y1) ⇒ (-1,3)

(x2,y2) ⇒ (-1,-3)

Slope = \frac{-3-3}{-1+1}

⇒ -6/0 (No slope)

If the denominator of a fraction is zero, the expression is not a legal fraction because it's overall value is undefined.

∴ There is no slope.

5) The given points are (1,-3) and (-1,-3)

(x1,y1) ⇒ (1,-3)

(x2,y2) ⇒ (-1,-3)

Slope = \frac{-3+3}{-1-1}

⇒ 0/-2

∴ The slope is zero.

5 0
4 years ago
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Find the surface area of a triangular prism
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Answer: 3.37 i think

Step-by-step explanation:

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3 years ago
13p - 3 = 5p + 13 find p please
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P=2. Hope this helps
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3 years ago
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What is the volume of this pyramid
irga5000 [103]

Check the picture below.

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{\textit{triangular base}}{\frac{1}{2}(14)(18)}\\[1em] h=30 \end{cases}\implies V=\cfrac{1}{3}\left( \cfrac{1}{2}(14)(18) \right)(30) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V=1260~\hfill

3 0
3 years ago
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