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4 years ago

After 5 minutes of a basketball game

Mathematics

2 answers:

astra-53 [7]4 years ago

7 0

Answer:

Something happens...

Step-by-step explanation:

Marrrta [24]4 years ago

3 0

Answer:

uh... continue?

Step-by-step explanation:

you can submit another question again because I think that you forgot to write the rest of the question

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shepuryov [24]

Step-by-step explanation:

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3 years ago

13. Mark has a board that is 12 feet long. He

horrorfan [7]

Answer:

1.5 feet

Step-by-step explanation:

12/8 = 1.5 feet

6 0

3 years ago

Pleas help me, this is confusing.

Dmitry_Shevchenko [17]

Ask your teacher or a family member

7 0

3 years ago

Read 2 more answers

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

I NEED HELP ASAP PLEASEEEE

aleksandrvk [35]

Answer: C. 512

Step-by-step explanation:

V= s^3

V= 8 x 8 x 8 = 512 cubic inches

4 0

3 years ago