Okay, I’m pretty sire this is right.
A: (-1, 3)
B: (-3, 2)
C: (-8, 3)
D: (-4, 3)
To do this problem (I am not completely confident in this) I am pretty sure you flip the signs for both the x and y values due to the rotation of the shape 180°, then add 6 to the y value.
Sixty two is your answer you’re adding all the sides
50%
You have half of 6 so the percentage would be half of 100
Answer:no
Step-by-step explanation:
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
