Linear functions are usually of degree 1. They are a straight line. y=mx+b
A point in quadrant 4 could be (-4,-2)<span />
<h2>Answer: slope = ¹¹/₁₃
</h2><h3>Step-by-step explanation: </h3>
The question gives us two points, (−13, −19) & (13, 3), from which we can find the slope and later the equation of the line.
Finding the Slope
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= ((3 - (-19)) ÷ (13 - (-13))
= 22 ÷ 26
= ¹¹/₁₃
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<em>Checking my answer:</em>
<em>We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. If the line passes through both of the points then we calculated the slope correctly.</em>
⇒ y + 19 = ¹¹/₁₃ (x + 13)
<em>I have included a Desmos Graph that I graphed using the information equation (including the slope) and the points given. </em>
Answer:
ahhhhhhhhhhhh too muchhhhhhhhhhhhhh
Step-by-step explanation:
Answer:
3.3m+1.4
Step-by-step explanation:
Multiply 5 and 0.9m
Multiply 5 and 0.5
5 times 0.9m is 4.5m
5 times 0.5 is 2.5
Multiply -3 and 0.4m
Multiply -3 and 0.7
-3 times 0.4m is -1.2m
-3 times -.7 is -2.1
4.5m+ 2.5 -1.2m-2.1
Which is 3.3m+1.4
Hope this helps!