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Luba_88 [7]
3 years ago
13

Simplify (sin^4(x) - cos^4(x)) / (sin^2(x) - cos^2(x))

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Using the trig. identity

sin²x + cos²x = 1

Given

\frac{sin^4x-cos^4x}{sin^2x-cos^2x}

sin^{4}x - cos^{4}x ← is a difference of squares and factors as

(sin²x - cos²x)(sin²x + cos²x), then fraction becomes

= \frac{(sin^2x-cos^2x)(sin^2x+cos^2x)}{sin^2x-cos^2x} ← cancel (sin²x - cos²x) on numerator/ denominator

= sin²x + cos²x

= 1

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RSTU is a parallelogram. Solve for x. ANSWERS: A) –5 B) 10 C) 8 D) 0
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Step-by-step explanation:

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3 years ago
Which of the following is a factor of 1331x3 − 8y3?
Cloud [144]

Answer:

The factor is 11x - 2y ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- If we want to factorize x³ - y³

- The binomial x³ - y³ is different of two cubes, because x³ is cube x

  and y³ is cube y

- The difference of two cubes has two factors one two two terms and

  the other is three terms

- To factorize it we find the ∛x³ and ∛y³

→ ∛x³ = x and ∛y³ = y

→ Then the first factor is (x - y)

→ We find the second factor from the first factor

→ square x

→ square y

→ Multiply x and y and put them between x² and y² with opposite sign

  of the first factor

→ The second factor is (x² + xy + y²)

* Lets do the same with 1331x³ - 8y³

∵ \sqrt[3]{1331x^{3}}=11x

∵ \sqrt[3]{8y^{3}}=2y

∴ The first factor is (11x - 2y)

∵ (11x)² = 121x²

∵ (2y)² = 4y²

∵ 11x × 2y = 22xy

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∴ The second factor is (121x² + 22xy + 4y²)

∴ <em>The factor is 11x - 2y  </em>

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A rectangular prism has a width of 16 inches and a length of 10 inches. The volume of the rectangular prism is decreasing at a r
frosja888 [35]

Answer:

-3.47 inches per minute

Step-by-step explanation:

Let the height be 'h' for any time 't'.

Given:

Length of the prism (L) = 10 in

Width of the prism (w) = 16 in

The rate of change of volume of prism is, \frac{dV}{dt}=-555\ in^3/min (The negative sign implies the volume decreases with time.)

Now, rate of change of height of prism = \frac{dh}{dt}=?

Length and width remains constant.

Now, we know that, volume of a rectangular prism is given as:

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V=Lwh\\\\V=10\times 16\times h\\\\V=160h

Now, differentiating both sides with respect to time 't', we get:

\frac{dV}{dt}=\frac{d}{dt}(160h)

Plug in the given values and solve for \frac{dh}{dt}. This gives,

-555=160\times \frac{dh}{dt}\\\\\frac{dh}{dt}=\frac{-555}{160}\\\\\frac{dh}{dt}=-3.47\ in/min

The negative sign implies the height decreases with time.

Therefore, the the rate of change, in inches per minute, of the height when the height is 3 inches is -3.47 inches per minute.

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