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FinnZ [79.3K]
3 years ago
7

A person with emphysema will exhibit signs of select one:

Biology
1 answer:
Orlov [11]3 years ago
5 0
Emphysema is a kind of chronic obstructive pulmonary disease or COPD that which involves physiological abnormalities which includes loss of lung elasticity and air sac enlargement. It all starts when the alveoli or the air sac at the end of the bronchioles becomes enlarged due to its walls breaking down or are destroyed, collapsed, narrowed, stretched or over-inflated. Because of this, there will be fewer and larger damaged sacs which would eventually result to a reduced oxygen and carbon dioxide exchange in the surface area of the lungs. This would lead to a medical condition termed as respiratory acidosis because the lungs are incapable of removing enough carbon dioxide produced by the body.
Therefore, the answer is letter C. CHRONIC RESPIRATORY ACIDOSIS.
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In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrin
meriva

Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

  • long stems are dominant to short stems
  • purple flowers are dominant to white,
  • round peas are dominant to wrinkled

  • Each trait is determined by a single, different gene.

  • A heter0zyg0us plant is self-crossed
  • F1) 2,048 descendants

Let us name te alleles as follows

  • L ⇒ Long stem
  • l ⇒ Short stem
  • P ⇒ Purple flowers
  • p ⇒ white flowers
  • R ⇒ Round peas
  • r ⇒ wrinkled peas

Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

  • Stems

Parental) Ll  x  Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

     <u>3/4 long stem,</u> 1/4 short stem

  • Flower color

Parental) Pp  x  Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

     <u>3/4 purple flowers</u>, 1/4 white flowers

  • Peas

Parental) Rr  x  Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

     3/4 round peas, <u>1/4 wrinkled peas</u>

Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

<u><em>Note</em></u><em>: The symbol - is representing either a dominant or a recessive allele.</em>

From the crosses, we know that

  • 3/4 are long stemmed,
  • 3/4 have purple flowers, and
  • 1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr =<u> 9/64 L-P-rr</u>

Knowing that  the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

<em>We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.</em>

<em />

<em />

You will learn more about trihybrid crosses at

brainly.com/question/21942441

brainly.com/question/7333760

brainly.com/question/6764853

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