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Bezzdna [24]
3 years ago
9

Solve the inaquality 2(x-1)>8

="2(x - 1) \geqslant 8" alt="2(x - 1) \geqslant 8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0
<span>2(x-1)</span>≥<span>8

1.  Divide both sides by 2 on the way towards isolating x on the left side:
     x-1 </span>≥ 4
2.  Add  1 to both sides to isolate x:     x≥5

That's it.  The solution set consists of all real numbers = to or greater than 5.

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The combined area of a pair of congruent rectangles can be represented, in square units, by the expression 18y^2-818y 2 −8. The
sveta [45]

Answer:

Perimeter = 12y

Step-by-step explanation:

Given

Area = 18y^2 - 8 -- two rectangles

Required

Determine the perimeter of one of the rectangles

First, calculate the area (A) of 1 rectangle

A =\frac{1}{2}Area

A =\frac{1}{2}(18y^2 - 8)

A =9y^2 - 4

Express as difference of two squares

A =(3y - 2)(3y+2)

Area is calculated as:

A = Length * Width

So, by comparison:

Length = 3y - 2

Width = 3y + 2

The perimeter is:

Perimeter = 2 *(Length + Width)

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8 0
2 years ago
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erma4kov [3.2K]

Answer:

b = 77

Step-by-step explanation:

a² + b² = c²

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b² = 7225 - 1296

b² = 5929

\sqrt{b^2} =\sqrt{5929}

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3 0
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Step-by-step explanation:

3 0
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algol [13]

Answer:

72

Step-by-step explanation:

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7 0
3 years ago
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Andrews [41]

Answer:

3/110

Step-by-step explanation:

x = .0272727 repeating

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Subtract the first equation from the second

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------------------------------------

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Divide each side by 99

99x/99 = 2.7/99

x = 27/990

x =3/110

4 0
2 years ago
Read 2 more answers
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