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Bezzdna [24]
3 years ago
9

Solve the inaquality 2(x-1)>8

="2(x - 1) \geqslant 8" alt="2(x - 1) \geqslant 8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0
<span>2(x-1)</span>≥<span>8

1.  Divide both sides by 2 on the way towards isolating x on the left side:
     x-1 </span>≥ 4
2.  Add  1 to both sides to isolate x:     x≥5

That's it.  The solution set consists of all real numbers = to or greater than 5.

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The table show the age in years of employees in a company
adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0
3 years ago
Read 2 more answers
98675465791851234567890 divide 12345678901234567890987654321
azamat

Answer:

7.9927128e-6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please solve x^2-8x=8
Varvara68 [4.7K]

Answer:4^2-(8x1)=8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!!
Nesterboy [21]

Answer:

for Mr farley I got 70 and for Mr samuels I got also 70 and there is no difference because they both have the same mean I hope I helped

7 0
3 years ago
In an experiment to determine whether there is a systematic difference between the weights obtained with two different mass bala
Maslowich

Answer:

H0: μd=0 Ha: μd≠0

t= 0.07607

On the basis of this we conclude that the mean weight differs between the two balances.

Step-by-step explanation:

The null and alternative hypotheses as

H0: μd=0 Ha: μd≠0

Significance level is set at ∝= 0.05

The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571

The test statistic under H0 is

t = d/ sd/ √n

Which has t distribution with n-1 degrees of freedom

Specimen        A               B           d = a - b         d²

1                     13.76        13.74         0.02           0.004

2                    12.47        12.45          0.02         0.004

3                    10.09        10.08           0.01        0.001

4                       8.91       8.92          -0.01          0.001

5                     13.57      13.54           0.03        0.009

<u>6                     12.74      12.75          -0.01        0.001</u>

<u>∑                                                      0.06         0.0173</u>

d`= ∑d/n= 0.006/6= 0.001

sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882

sd= 0.05368

t= 0.001/ 0.05368/ √6

t= 0.18629/2.449

t= 0.07607

Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.

3 0
3 years ago
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