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Furkat [3]
3 years ago
12

What is the area of a trapezoid with bases of 15.8 yd and 21.8 yd and a height of 11.7 yd?

Mathematics
2 answers:
DedPeter [7]3 years ago
7 0

Answer:

B) 219.96 yd2

Step-by-step explanation:

The formula for finding the area of a trapezoid is:

(a + b) /2*h

Now you would plug in the numbers

(15.8 + 21.8) /2*11.7

Now solve this in order of operations

(15.8 + 21.8) /2*11.7

37.6/2*11.7

18.8*11.7

219.96

DedPeter [7]3 years ago
3 0

Add the bases together, divide that by 2 then multiply by the height.

15.8 + 21.8 = 37.6

37.6/2 = 18.8

18.8 x 11.7 = 219.96 yd^2

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Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +
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Answer:

36i^{2}+48i+16

Step-by-step explanation:

(4+6i)^{2} is essentially (4+6i)(4+6i) (you are squaring (4+6i), so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

(4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i)

((4*4)+(4*6i)+(6i*4)(6i*6i))

After doing so, you would end up with 16+24i+24i+36i^{2}, and after combining like terms, 16+48i+36i^{2}.

To write the expression in standard form, though, just order the terms from highest to lowest power!

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