Remember the equation for slope is y=mx+b {m=slope, and b=y-intercept.} {Slope= rise/run}
1.) y= 2x+0
2.) y= -3/4x+0.5
P.S.: hope I helped :)
Step-by-step explanation:
✧ ![\underline{ \underline{ \large{ \tt{G \: I \: V \: E\: N}}} } :](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BG%20%5C%3A%20I%20%5C%3A%20V%20%5C%3A%20E%5C%3A%20N%7D%7D%7D%20%7D%20%3A%20%20)
✧ ![\underline{ \underline{ \large{ \tt{T\: O \: \: F\: I\: N\: D}}}}:](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BT%5C%3A%20O%20%5C%3A%20%20%5C%3A%20F%5C%3A%20I%5C%3A%20N%5C%3A%20D%7D%7D%7D%7D%3A%20)
✧ ![\underline{ \underline{ \large{ \tt{S \:O \: L \: U \: T \: I \: O \: N}}}} :](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Clarge%7B%20%5Ctt%7BS%20%5C%3AO%20%5C%3A%20L%20%5C%3A%20U%20%5C%3A%20T%20%5C%3A%20I%20%5C%3A%20O%20%5C%3A%20N%7D%7D%7D%7D%20%3A%20)
❀ ![\large{ \text{When \: x = 2 ,\: f}(2) = 2 \tt{ \times 2 - 6}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctext%7BWhen%20%5C%3A%20x%20%3D%202%20%2C%5C%3A%20f%7D%282%29%20%3D%202%20%5Ctt%7B%20%5Ctimes%202%20-%206%7D%7D)
⟼ ![\large{ \text{f(2) = 4 - 6 = \boxed{ \large{ \text{ - 2}}}}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%5Ctext%7Bf%282%29%20%3D%204%20-%206%20%3D%20%20%5Cboxed%7B%20%5Clarge%7B%20%5Ctext%7B%20-%202%7D%7D%7D%7D%7D)
♨ ![\boxed{ \boxed{ \large{ \text{OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bold{ \text{ - 2}}}}}}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cboxed%7B%20%5Clarge%7B%20%5Ctext%7BOUR%5C%3A%20FINAL%20%5C%3A%20ANSWER%20%3A%20%20%5Cboxed%7B%20%5Cunderline%7B%20%5Cbold%7B%20%5Ctext%7B%20-%202%7D%7D%7D%7D%7D%7D%7D%7D)
Hope I helped ! ♡
Have a wonderful day / night ! ♪
Let me know if you have any questions regarding my answer! ☄
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Answer:
27/9
Step-by-step explanation:
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
35^67
Step-by-step explanation: