Ask question

Ask question

All categories

3 years ago

14

Is it always, sometimes, or never true that a scatter plot that shows a positive association suggests that the relationship is p

roportional?

1 answer:

zhenek [66]3 years ago

4 0

The answer is sometimes

You might be interested in

How much cardboard is needed to make the cereal box shown below? You are finding the surface area of this box.

Irina-Kira [14]

i would recommend asking a tutor because some people answer just to get points

8 0

3 years ago

The area of the above polygon is ?<br>the answer is not 44

vitfil [10]

Check the picture below.

you really have two rectangles, a 6x10 and a 6x5, and surely you know what those areas are, so sum them up, and that's the area of the polygon.

6 0

4 years ago

The prism has a surface area of 1312 mm2.

777dan777 [17]

So each dimention is 32 by 8 by 10
so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312

if halved
just divide each by 2
(2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328
the new surface area is 328 mm^2

4 0

3 years ago

Can u please explain how to do this?

mafiozo [28]

B is the correct answer.
8 x 35 = 280

5 0

4 years ago

Read 2 more answers

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

4 years ago

Read 2 more answers