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MaRussiya [10]
3 years ago
13

Find an equivalent ratio.7:13​

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
6 0

Answer:

7/13 = (7 × 2)/(13 × 2) = 14/26 = 14 : 26 is one equivalent ratio

Step-by-step explanation:

I hope this helps

Sliva [168]3 years ago
5 0

Answer:

7/20

Step-by-step explanation:

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To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

14x^2-8+5x-6x^2+2x

group the x^2 (add 14x^2 to -6x^2)

8x^2-8+5x+2x

group the x's together (add 5x and 2x together)

8x^2+7x-8

Your answer will be d) 8x^2+7x-8



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Given one zero of the polynomial function, find the other zeros.
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these.  The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a.  3I   1   3   -34   48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I   1    3    -34    48

   _____________

      1

then multiply it by the 3 and put it up under the 3.  Add those together:

3I    1    3    -34    48

           3

----------------------------

      1     6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I    1     3     -34     48                                                                                                    

             3      18

_________________

      1      6     -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I      1      3      -34      48

                3       18     -48

___________________

        1       6      -16       0

That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

x^2+6x-16=0

Factoring that depressed polynomial will give you the remaining zeros.  Because this was originally a third degree polynomial, there are 3 zeros as solutions.  Factoring that depressed polynomial gives you the remaining zeros of x = -8 and x = 2

I am assuming that since you are doing synthetic division that you have already learned the quadratic formula.  You could use that or just "regular" factoring would do the trick on all of them.

Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!        

4 0
3 years ago
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