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3 years ago

19, 25, 31, 37 What’s the 52nd term?

Mathematics

1 answer:

grin007 [14]3 years ago

6 0

All you have to do is find the rule, the rule for this is 6 so just multiply 3 times 52 and add 19, your answer is 175

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I need help with #32 it is due tomorrow.

OverLord2011 [107]

I believe the answer is 5x

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3 years ago

Apply the Pythagorean Theorem to find the distance between points A and C.

Rashid [163]

Answer:

Step-by-step explanation:

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3 years ago

Can someone help! I know the answer I just need step by step!

baherus [9]

Answer:

$4 \sqrt{2}$

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

$\implies \sqrt{32}=\sqrt{16 \cdot 2$

Apply exponent rule $\sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}$

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$\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}$

Apply exponent rule $\sqrt{a^2}=a$

$\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}$

6 0

2 years ago

Read 2 more answers

Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

4 0

3 years ago

a straight line has a equation 4x + 3y = 12 . find the gradient of the line and the coordinates of the point where this line cro

Komok [63]

4x + 3y = 12
3y = -4x + 12
y = -4/3x + 4........so the slope (or gradient) is -4/3...because in y = mx + b form, the slope(gradient) is in the m position and the y int is in the b position....so if u wanted to know the y axis, it would be (0,4)

the x intercept (where the line crosses the x axis) can be found by subbing in 0 for y in the original equation or the slope intercept equation, and solving for x.
4x + 3(0) = 12
4x = 12
x = 12/4 = 3....so the x intercept is (3,0)

4 0

3 years ago