Determine the height of a square pyramid with a volume of 225 cubic inches and a base edge of 5 inches.

Mathematics

1 answer:

ss7ja [257]3 years ago

5 0

Answer:

h = 27 inches

Step-by-step explanation:

Given that,

The volume of a square pyramid, V = 225 inches³

The base edge of a square pyramid, b = 5 inches

We need to find the height of a square pyramid. The formula for the volume of a square pyramid is given by :

$V=\dfrac{1}{3}B\times h$

B is area of base, B = b²

So,

$h=\dfrac{3V}{b^2}\\\\h=\dfrac{3\times 225}{5^2}\\\\h=27\ \text{inches}$

So, the height of the square pyramid is 27 inches.

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When you do the calculation; $\frac{422}{59}=7.15$ You get 7.15 shelves. Clearly you cannot have .15 of a shelf so the logician in me wants to say you need 8 shelves!

But if the assignment is aimed estimation skills, (Which is what I assume is being implied by the title of the assignment), then the easier calculation of $\frac{420}{60}=7$ is probably what the teacher was hoping for.

You might have been accidentally been calculating $\frac{59}{422} =.139$ . Remember division is NOT communitive! i.e. $1\div2\neq2\div1$ .

From the image;
The first step was to see that 59 can not go into 4..resulting in the zero above the 4, multiplying 0 by 59 and subtracting 0 from 4.

The second step begins by bringing down the 2, seeing that 59 can not go into 42..resulting in the zero above the 2, multiplying 0 by 59 and subtracting 0 from 42.

The third step begins by bringing down the 2, seeing that 59 can go into 422 7 times (I tested this on the right by a short multiplication problem)..resulting in the 7 above the 2, multiplying 7 by 59 and subtracting 413 from 42.

This process continues....