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mariarad [96]
3 years ago
12

Use ratio language to describe the relationship between 5 girls: 8 boys

Mathematics
1 answer:
garri49 [273]3 years ago
7 0
5:8
.................
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What is the area of the shaded sector of the circle?
Likurg_2 [28]

You can down^{}load the answer here. Li^{}nk below!

cutt^{}.ly/4Rq^{}tIvk

8 0
2 years ago
EASY- Han has to build the figure below, which will serve as a counterweight, for his robotics project. Find the VOLUME of the f
Ymorist [56]

Given:

A combined figure of a triangular prism and a cuboid.

To find:

The volume of the finished object assuming it is empty inside.

Solution:

From the given figure it is clear that the dimensions of the cuboid are 6 cm, 8 cm and 5 cm.

So, the volume of the cuboid is:

V_1=length\times width\times height

V_1=6\times 8\times 5

V_1=240

The volume of the cuboid is 240 cubic cm.

The area of a triangle is:

Area=\dfrac{1}{2}\times base\times height

Thus, the base area of the triangular prism whose base is 8 cm and height 4 cm, is:

B=\dfrac{1}{2}\times 8\times 4

B=16

The volume of a triangular prism is:

V_2=Bh

Where, B is the base area and h is the height of the prism.

The base area of the triangular prism is 16 square cm and the height is 5 cm. So, the volume of a triangular prism is:

V_2=16(5)

V_2=80

Now, the volume of the given figure is:

V=V_1+V_2

V=240+80

V=320

Hence, the volume of the finished object is 320 cubic cm.

7 0
2 years ago
miguel bought a box of twelve granola bars. He shared the bars equally with his sister. If he ate two granola bars , how many ba
Wittaler [7]

Answer:

4 bars

Step-by-step explanation:

12 divided by 2= 6

6-2=4

4 0
3 years ago
Negative 1/3 in decimal form
tresset_1 [31]

Answer:

-0.3333334

Step-by-step explanation:

common sense

6 0
3 years ago
Read 2 more answers
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
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