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3 years ago

12

Use ratio language to describe the relationship between 5 girls: 8 boys

1 answer:

garri49 [273]3 years ago

7 0

5:8
.................

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M is directly proportional to r2.when r=2,m=14.Work out the value of m when r=12

valentinak56 [21]

Answer:

504

Step-by-step explanation:

In the attached file

Hope it helps

4 0

3 years ago

A computer chip has dimensions of 8mm x 8mm. the scale drawing shows 4cm by 4cm. the answer is 1cm represents 2mm but I don't kn

Andru [333]

$Change\ all\ dimensions\ to\ the\ same\ unit. \\ \\ \\ \\ 4cm==\textgreater\ 400\ mm$ $Work\ out\ the\ Scale\ factor, \\ \\ \\ \\ Scale\ factor= { \frac{Scaled\ dimension\ (same\ side)}{Actual\ dimension\ (same\ side)} } \\ \\ = { \frac{400}{8} } \\ \\ = 50$
$1\ mm\ on\ actual= 50\ mm\ on\ scaled. \\ \\ 2\ mm\ represents\ 1\ cm\ on\ scaled.$

6 0

3 years ago

For the triangle shown below, complete the following table.

dem82 [27]

Answer:

Step-by-step explanation:

In the given triangle

With reference angle A

perpendicular (P) = 3

hypotenuse (h) = 5

So sin A = p/h = 3/5

and

With reference angle C

perpendicular (p)= 4

hypotenuse (h) = 5

Sin C = p/h = 4/5

hope it helps :)

3 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

What is 5m2- 15m- 200

vitfil [10]

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40

1 40

2 20

4 10

5 8

Based on the middle term we know that 5 and 8 are our best option.

5(m 5) (m 8)

We know the signs have to be one + and one - because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

3 0

3 years ago