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DIA [1.3K]
3 years ago
7

How many inches are in 1 mile? (5280ft = 1mi; 12in = 1ft)

Mathematics
2 answers:
Andreyy893 years ago
8 0

Answer:

63360

Step-by-step explanation:

5280 × 12 = 63360

7nadin3 [17]3 years ago
4 0

1 mile * 5280 ft * 12 in = 63360 in

There are 63360 inches in one mile

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Write the number in standard notation. 9.07 x 10−2
77julia77 [94]
Move over the # of decimal places as the negative exponent. 0.0907 is the correct answer!
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4 0
3 years ago
Read 2 more answers
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
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so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
6 cm
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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olga2289 [7]

Answer:

No Solution

Explanation:

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Expand

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3(-15b - 2): -45b - 6

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Subtract 5 From Both Sides

15 - 45b - 15 = -45b - 6 - 15

Simplify

-45b = -45b - 21

Add 15b To Both Sides

-45b + 15b = -45b - 21 + 15b

Simplify

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8 0
4 years ago
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There are 30 days in June and only three of those days are multiples of 8 so you have the probability of 3 out of 30. 
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3 years ago
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