3 years ago

A^3-b^3/a^3b^3+a^2b^4+ab^5

1 answer:

8 0

Hello,

If the question is to simplify then

$\dfrac{ a^{3}-b^{3}}{a^{3}b^{3}+a^{2}b^{4}+ab^{5}}$

$=\dfrac{ (a-b)(a^{2}+ab+b^{2})}{ab^{3}(a^{2}+ab+b^{2})}$

$=\dfrac{ a-b}{ab^{3}}$

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