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sesenic [268]
3 years ago
9

A^3-b^3/a^3b^3+a^2b^4+ab^5

Mathematics
1 answer:
Len [333]3 years ago
8 0
Hello,

If the question is to simplify then

\dfrac{ a^{3}-b^{3}}{a^{3}b^{3}+a^{2}b^{4}+ab^{5}}

=\dfrac{ (a-b)(a^{2}+ab+b^{2})}{ab^{3}(a^{2}+ab+b^{2})}

=\dfrac{ a-b}{ab^{3}}







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