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asambeis [7]
3 years ago
15

The radius of a circle is 6 millimeters. What is the circle's circumference?

Mathematics
2 answers:
Ymorist [56]3 years ago
5 0

Answer:

the circumference is 37.7

Gala2k [10]3 years ago
4 0

Answer:

C =37.68 mm

Step-by-step explanation:

The circumference of a circle is given by

C = 2*pi*r

C = 2(3.14)*6

C =37.68 mm

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If s = 1 over 3 unit and A = 18s2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.)
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Whats the variable for -11b+7+=40
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Step-by-step explanation:

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Find the measure of arc DB in P<br><br>please hurry if you can​
jeyben [28]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: m \overbrace{DB}  + m \overbrace{TB}  = 180 \degree

[ linear pair ]

\qquad \tt \rightarrow \: m \overbrace{DB}  + 90 \degree  = 180 \degree

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8 0
2 years ago
FURTHER MATHEMATICS Use determinants to solve the systems of equation:
maw [93]

Answer:

Step-by-step explanation:

\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\

\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\

\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\

\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\

\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.

8 0
3 years ago
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