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lesya692 [45]
3 years ago
15

The measurement of the height of 600 students of a college is normally distributed with a mean of

Mathematics
1 answer:
ioda3 years ago
5 0

Answer:

68

Step-by-step explanation:

We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.

We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.

This can be expressed as;

P(170<X<180)

This can be evaluated in Stat-Crunch using the following steps;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 175 and that of the standard deviation as 5

Then input the values 170 and 180

click compute

Stat-Crunch returns a probability of approximately 68%

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X-2y=5 2x-4y=10
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Step-by-step explanation:

X-2y=5 ; 2x-4y=10

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3 years ago
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3 years ago
Subtract 7x^2−5xy+8y2 from −2x^2−15xy+9y^2
Digiron [165]

Answer

Subtract 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2

then;

-2x^2 -15xy+9y^2 - (7x^2 -5xy+8y^2)

Remove the bracket we have;

-2x^2 -15xy+9y^2 - 7x^2 + 5xy - 8y^2

Like terms are those terms which have same variable to the same power.

Combine like terms;

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Therefore, Subtracting 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2 we get -9x^2 -10xy+y^2

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Vsevolod [243]

Answer:

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Step-by-step explanation:

Take for instance 2 linear functions,  and

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3 years ago
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