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Margaret [11]
4 years ago
8

Whats 15.186 rounded to the nearest tenth

Mathematics
2 answers:
Ivenika [448]4 years ago
7 0
15.2 because the 8 is 5 and above with brings it to the nearest 10th;
if it was 4 and under it would be rounded to 15.1
Sveta_85 [38]4 years ago
3 0
Answer:  15.2    .
_____________________
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Suppose a simple random sample of size 50 is selected from a population with σ=10σ=10. Find the value of the standard error of t
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a) \sigma_{\bar x} = 1.414

b) \sigma_{\bar x} = 1.414

c) \sigma_{\bar x} = 1.414

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Step-by-step explanation:

Given that:

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Size of the sample n = 50

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The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

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b) When the population size N= 50000

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Therefore;

The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}

\sigma_{\bar x} = 1.414

c)  When the population size N= 5000

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Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}

\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}

\sigma_{\bar x} = 1.414

d) When the population size N= 500

n/N = 50/500 = 0.1 > 0.05

So; the finite population of the standard error is applicable in this scenario;

Therefore;

The standard error is determined as:

\sigma _{\bar x} = \sqrt{\dfrac{N-n}{N-1} }\dfrac{\sigma}{\sqrt{n} } }

\sigma _{\bar x} = \sqrt{\dfrac{500-50}{500-1} }\dfrac{10}{\sqrt{50} } }

\sigma _{\bar x} = 1.343

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4 years ago
What fraction represents 70%
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Answer:

7/10

Step-by-step explanation:

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