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Nat2105 [25]
3 years ago
11

How do you write 403.608 in word form

Mathematics
2 answers:
rodikova [14]3 years ago
8 0
4 is in the hundreds place
3 is in the ones place
6 is in the tenths place
8 is in the thousanths place so
four hundred and three point or dot six zero eight or
four hundred and three and six hundred and eight thousanths

Alexxx [7]3 years ago
3 0
403.608 as word form is:

Four hundred three and six hundred eight thousandths.

You might be interested in
The rental car agency has 30 cars on the lot. 10 are in great shape, 16 are in good shape, and 4 are in poor shape. Four cars ar
Korolek [52]

Complete Question:

The rental car agency has 30 cars on the lot. 10 are in great shape, 16 are in good shape, and 4 are in poor shape. Four cars are selected at random to be inspected. Do not simplify your answers. Leave in combinatorics form. What is the probability that:

a. Every car selected is in poor shape

b. At least two cars selected are in good shape.

c. Exactly three cars selected are in great shape.

d. Two cars selected are in great shape and two are in good shape.

e. One car selected is in good shape but the other 3 selected are in poor shape.

Answer:

a

   P_A = \frac{^4 C_4}{^{30}C_{4}}

b

  P_B = \frac{[^{16} C_2 *^{14} C_2 ] +[^{16} C_3 *^{14} C_1 ] + ^{16} C_4}{^{30}C_{4}}

c

  P_C = \frac{^{10} C_3 *^{20} C_1 }{^{30}C_{4}}

d

   P_D = \frac{^{10} C_2 *^{16} C_2 }{^{30}C_{4}}

e

   P_E = \frac{^{16} C_1 *^{4} C_3 }{^{30}C_{4}}

Step-by-step explanation:

From the question we are told that

 The number of car in the parking lot is  n =  30  

  The number of cars in great shape is  k =  10

   The number of cars in good shape is r = 16

    The number of cars in poor shape is q = 4

The number of cars that were selected at random is N= 4

Considering question a

    Generally the number of way of selecting four cars that are in a poor shape from number of cars that are in poor shape is

            ^{q} C_{N}

=>        ^{4} C_{4}

Here C stands for combination.

 Generally the number of way of selecting four cars that are in a poor shape from total number of cars  in the parking lot is

          ^{n} C_{N}

=>      ^{30} C_{4}

Generally the probability that every car selected is in poor shape  is mathematically represented as

       P_A = \frac{^4 C_4}{^{30}C_{4}}

Considering question b

Generally the number of way of selecting 2 cars that are in good shape from number of cars that are in good shape is

            ^{r} C_{2}

=>        ^{16} C_{2}

Here C stands for combination.

 Generally the number of way of selecting the remaining 2 cars  from the remaining number of cars  in the parking lot is

          ^{n-r} C_{2}

=>      ^{30-16} C_{2}

=>      ^{14} C_{2}

Generally the number of way of selecting 3 cars that are in good shape from number of cars that are in good shape is

            ^{r} C_{3}

=>        ^{16} C_{3}

 Generally the number of way of selecting the remaining 1 cars  from the remaining number of cars  in the parking lot is

          ^{n-r} C_{1}

=>      ^{30-16} C_{1}

=>      ^{14} C_{1}

Generally the number of way of selecting 4 cars that are in good shape from number of cars that are in good shape is

            ^{r} C_{4}

=>        ^{16} C_{4}

Generally the probability that at least two cars selected are in good shape

       P_B = \frac{[^{16} C_2 *^{14} C_2 ] +[^{16} C_3 *^{14} C_1 ] + ^{16} C_4}{^{30}C_{4}}

Considering question c

Generally the number of way of selecting 3 cars that are in great shape from number of cars that are in great shape is      

            ^{k} C_{3}

=>        ^{10} C_{3}

 Generally the number of way of selecting the remaining 1 cars  from the remaining number of cars  in the parking lot is

          ^{n-k} C_{1}

=>      ^{30-10} C_{1}

=>      ^{20} C_{1}

Generally the probability of selecting exactly three cars selected are in great shape is

        P_C = \frac{^{10} C_3 *^{20} C_1 }{^{30}C_{4}}

Considering question d

Generally the number of way of selecting 2 cars that are in good shape from number of cars that are in good shape is

            ^{r} C_{2}

=>        ^{16} C_{2}

Generally the number of way of selecting 2 cars that are in great shape from number of cars that are in great shape is      

            ^{k} C_{2}

=>        ^{10} C_{2}

Generally the probability that two cars selected are in great shape and two are in good shape.

              P_D = \frac{^{10} C_2 *^{16} C_2 }{^{30}C_{4}}

Considering question e

Generally the number of way of selecting 1 cars that is in good shape from number of cars that are in good shape is

            ^{r} C_{1}

=>        ^{16} C_{1}

    Generally the number of way of selecting 3 cars that are in a poor shape from number of cars that are in poor shape is

            ^{q} C_{3}

=>        ^{4} C_{3}

Generally the probability that one car selected is in good shape but the other 3 selected are in poor shape is

         P_E = \frac{^{16} C_1 *^{4} C_3 }{^{30}C_{4}}

4 0
3 years ago
M={2,3,4,6,7} D={2,4,6} intersection of M and D. union of M and D​
SCORPION-xisa [38]

Answer:

M ∪ D= { 2, 3, 4 , 6 , 7}

M ∩  D= { 2, 4 , 6}

Step-by-step explanation:

UNION OF SETS : The union of two sets P and Q  is the set of elements which belong in A or in B or in both.

Here,  M =  {2,3,4,6,7}   D  =   {2,4,6}

⇒ M ∪ D= { 2, 3, 4 , 6 , 7}

INTERSECTION OF SETS :  The intersection  of two sets P and Q  is the set of elements which belong in A and B both.

Here,  M =  {2,3,4,6,7}   D  =   {2,4,6}

         ⇒ M ∩  D= { 2, 4 , 6}

3 0
3 years ago
Oof, I'm to tired to remember how to do this T-T
scoundrel [369]

Answer:

D

Step-by-step explanation:

Equation of the line

y - y1 = m(x - x1)

y - (-4) = 1/3 (x - 3)

y + 4 = 1/3x - 1

y = 1/3 x - 5

the graph that intercept y axis in -5 is the graph D

3 0
3 years ago
Read 2 more answers
What is 4million 2hunderd thousand 6 hundred 52 in digitss​
julsineya [31]

Answer:

one thousand, seven hundred twenty-eight

7 0
3 years ago
Help!!!!!111! (picture shown) Math.... Help fast
Nana76 [90]

Answer:

B

Step-by-step explanation:

Hi,

2πr is the formula for circumference, you know your diameter is 4cm and radius is half of the diameter, so your radius is 2cm.

To find the circumference, you have to multiply 2 by 2 and pie. 2 x 2 is 4. So 4 times pie. B is your correct answer.

I hope this helps :)

7 0
3 years ago
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