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Mama L [17]
4 years ago
11

The section called Breaking Substitution Ciphers (p. 166) describes a "random substitution cipher," in which each letter of the

alphabet is randomly replaced with a different letter or character i.e. A→T, B→F… What makes a random substitution cipher more secure than a Caesar shift?
Computers and Technology
1 answer:
timofeeve [1]4 years ago
5 0

Answer: Compared to a Caesar shift, the random substitution cipher offers many more possibilities, because the encryption is randomly chosen.

Explanation:

A Caesar Cipher is also a type of substitution cipher, but instead of doing it randomly, it shifts the alphabet by a certain number of characters. Therefore, the answer to decrypt the message is simply to figure out that number.

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Which of the following set of instructions defines an algorithm in the formal, strict sense?
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Whats the flow in this code, and whats the risk that its creating and what can i do to fix it? (c language)
Advocard [28]

Answer:

The risk is a buffer overflow.

Explanation:

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6 0
3 years ago
Write a function solution that returns an arbitrary integer which is greater than n.
Aleksandr-060686 [28]

Answer:

   public static int greaterThanInt(int n){

       return n+10;

   }

Explanation:

This is a very simple method in Java. it will accept an argument which is an integer n and return n+10 since the question requires that an arbitrary integer greater than n be returned adding any int value to n will make it greater than n.

A complete java program calling the method is given below:

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        System.out.println("Please enter an integer");</em>

<em>        int n = in.nextInt();</em>

<em>        int greaterInt = greaterThanInt(n);</em>

<em>        System.out.println("You entered "+n+", "+greaterInt+" is larger than it");</em>

<em>    }</em>

<em>    public static int greaterThanInt(int n){</em>

<em>        return n+10;</em>

<em>    }</em>

<em>}</em>

4 0
4 years ago
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