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QveST [7]
4 years ago
12

The radius of a right circular cone is increasing at a rate of 1.6 in/s while its height is decreasing at a rate of 2.2 in/s. At

what rate is the volume of the cone changing when the radius is 135 in. and the height is 135 in.
Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
4 0

Answer:

Step-by-step explanation:

let radius=r

height=h

dr/dt=1.6 in/s

dh/dt=-2.2 in/s

volume v=1/3 πr²h

dv/dt=1/3 π[h*2r×dr/dt+r²×dh/dt]

when r=135 in

h=135 in

dv/dt=1/3 π[2×135×135×1.6+135²×(-2.2)]

=1/3 π[135²(3.2-2.2)]

=1/3π135²×1

=6075 π in³/s

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A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
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The angle between [A_F] and the base of the cone = 68.2°

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The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

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The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

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