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QveST [7]
3 years ago
12

The radius of a right circular cone is increasing at a rate of 1.6 in/s while its height is decreasing at a rate of 2.2 in/s. At

what rate is the volume of the cone changing when the radius is 135 in. and the height is 135 in.
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

Step-by-step explanation:

let radius=r

height=h

dr/dt=1.6 in/s

dh/dt=-2.2 in/s

volume v=1/3 πr²h

dv/dt=1/3 π[h*2r×dr/dt+r²×dh/dt]

when r=135 in

h=135 in

dv/dt=1/3 π[2×135×135×1.6+135²×(-2.2)]

=1/3 π[135²(3.2-2.2)]

=1/3π135²×1

=6075 π in³/s

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Answer:

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Step-by-step explanation:

3sin(2x) = 2sin(2x) + 1

3sin(2x) - 2sin(2x) = 1

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When a variable n = π/2, sin(π/2) = 1 [refer to the unit circle].

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Hope this helps!

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