Given:
The given equation is:
To find:
The solution for the given equation.
Solution:
We have,
On simplification, we get
Squaring both sides, we get
Divide both sides by -2.
Therefore, the correct option is B.
Answer:
every parallelogram is a square? False
every rectangle with four congruent sides is a square? True
every rectangle is a quadrilateral? True
every quadrilateral is a rectangle? False
Step-by-step explanation:
every parallelogram is a square?
A parallelogram has two opposite pairs of parallel lines and opposite congruent sides. A square needs to have 4 right angles and all sides need to be equal. In the restrictions of a parallelogram, these cannot be concluded, therefore parallelogram are not always squares.
every rectangle with four congruent sides is a square?
Square require 4 congruent sides and 4 right angles. Rectangles already have 4 right angles. If you add 4 congruent sides to the mix, it means that these rectangles are always squares.
every rectangle is a quadrilateral?
A quadrilateral is defined by a shape having 4 sides. Rectangles have 4 sides, so they fit into the category of quadrilaterals.
every quadrilateral is a rectangle?
A quadrilateral is a just a shape with four sides. We do not know if it has 4 right angles, so not every quadrilateral is a rectangle.
The answer is x(x-8)(x+8)
Here is the process;
x^3-64x
x(x^2-64)
You know that it will be a x- and a x+ becuase there is no middle x value
x(x-)(x+)
x(x-8)(x+8)
Answer:
(8, -22) All real numbers
Step-by-step explanation:
So since we already have the value of y lets Substitute;
3x + (-4x + 10) = 2
Distribute;
3x - 4x + 10 = 2
Collect like terms;
-1x + 10 = 2
Subtract 10 from both sides;
-1x = -8
Divide both sides by -1
x = 8
So now lets get the actual value for y by substituting x;
y = -4(8) + 10
y = -32 + 10
y = -22
(x, y) = (8, -22)
Given:
The two numbers are 1280 and 630.
To find:
The HCF of the given numbers.
Solution:
First write the given numbers in prime factorization form.
Now the product of all the common prime factors is known as the HCF of 1280 and 630.
Therefore, the HCF of 1280 and 630 is 10.
