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olchik [2.2K]
3 years ago
15

A law firm is going to designate associates and partners to a big new case. The

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

The system 800x+1300y=12300 and y = x+3 can be used to determine the number of associate assigned to the case and the number of partners assigned to the case where x represent the number of associates and y represent the number of partner

Step-by-step explanation:

Per day charge of each associate = $800

Per day charge of each partner = $1300

Total charged per day = $12300

Let,

x be the number of associates

y be the number of partners

According to given statement;

800x+1300y=12300        Eqn 1

y = x+3              Eqn 2

The system 800x+1300y=12300 and y = x+3 can be used to determine the number of associate assigned to the case and the number of partners assigned to the case where x represent the number of associates and y represent the number of partners

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Help me find the area of the shaded region
dalvyx [7]
I think it’s 50 but idk
7 0
3 years ago
Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




8 0
2 years ago
3
erastovalidia [21]

ummm i think is bussin dems toes, but im not sure

7 0
3 years ago
In quadrilateral QRST, Angle R S T measures (5x+15)°. Angle TQR measures (4x+3)°. Circle P is inscribed with quadrilateral Q R S
Assoli18 [71]

Answer:

105degrees

Step-by-step explanation:

Using the theorems that states that the sum of the opposite side of the quadrilateral is 180degrees, hence;

<RST + <TQR = 180

5x+15 + 4x+ 3 = 180

9x + 18 = 180

9x = 180 - 18

9x = 162

x = 162/9

x = 18

Since <RST = 5x+15

<RST = 5(18) + 15

<RST = 90 + 15

<RST = 105degrees

Hence the measure of <RST is 105degrees

7 0
2 years ago
Read 2 more answers
I need help!
blagie [28]

Here is the solution...

1) \sqrt[3]{135} \\

Solution

We can rewrite \sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}

Here, \sqrt[3]{27} = 3

Now substitute the value, we get

\sqrt[3]{135} = 3 \sqrt[3]{5}

The answer is 3\sqrt[3]{5}


2) -5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}

Here \sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\

Therefore, we get -5*2\sqrt[3]{5} = -10 \sqrt[3]{5}

The answer is-10 \sqrt[3]{5}[/tex]


2) 2\sqrt[3]{5} * 4\sqrt[3]{8}

Solution

\sqrt[3]{8} = 2

Now plug in the above in the given expression, we get

2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}                         {2*4*2 = 16]

The answer is 16\sqrt[3]{5}

8 0
3 years ago
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