Answer:
(1) Area of second triangle= 50 cm^2.
(2) Area of ΔABC=98 cm^2.
and Area of ΔDFG=175 cm^2.
Step-by-step explanation:
<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>
i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

(1)
for the first question:
we have a=2, b=5.
A=8 cm^2.
Hence,

B=50 cm^2.
Hence, the area of second triangle is 50 cm^2.
(2)
In second option we have:
a=6 and b=5.
A-B=77 cm^2.
A=77+B

Hence area of second triangle i.e. ΔDFG is 175 cm^2.
and area of first triangle i.e. ΔABC=175-77=98 cm^2.
ummm i think is bussin dems toes, but im not sure
Answer:
105degrees
Step-by-step explanation:
Using the theorems that states that the sum of the opposite side of the quadrilateral is 180degrees, hence;
<RST + <TQR = 180
5x+15 + 4x+ 3 = 180
9x + 18 = 180
9x = 180 - 18
9x = 162
x = 162/9
x = 18
Since <RST = 5x+15
<RST = 5(18) + 15
<RST = 90 + 15
<RST = 105degrees
Hence the measure of <RST is 105degrees
Here is the solution...
1) ![\sqrt[3]{135} \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%5C%5C)
Solution
We can rewrite ![\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here, ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%3D%203)
Now substitute the value, we get
![\sqrt[3]{135} = 3 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%203%20%5Csqrt%5B3%5D%7B5%7D)
The answer is ![3\sqrt[3]{5}](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7B5%7D)
2) ![-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}](https://tex.z-dn.net/?f=-5%5Csqrt%5B3%5D%7B40%7D%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3ESolution%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D-5%5Csqrt%5B3%5D%7B40%7D%20%3D%20-5%5Csqrt%5B3%5D%7B8%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here ![\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B3%7D%20%7D%20%3D%202%5C%5C)
Therefore, we get ![-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}](https://tex.z-dn.net/?f=-5%2A2%5Csqrt%5B3%5D%7B5%7D%20%3D%20-10%20%5Csqrt%5B3%5D%7B5%7D)
The answer is-10 \sqrt[3]{5}[/tex]
2) ![2\sqrt[3]{5} * 4\sqrt[3]{8}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B5%7D%20%2A%204%5Csqrt%5B3%5D%7B8%7D)
Solution
![\sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%202)
Now plug in the above in the given expression, we get
{2*4*2 = 16]
The answer is ![16\sqrt[3]{5}](https://tex.z-dn.net/?f=16%5Csqrt%5B3%5D%7B5%7D)