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____ [38]
3 years ago
10

We roll a fair die repeatedly until we see the number four appear and then we stop. The outcome of the experiment is the number

of rolls.a. Describe a sample space Ohm and a probability measure P to model this situation. b. Calculate the probability that the number four never appears.
Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

0

Step-by-step explanation:

given that we roll a fair die repeatedly until we see the number four appear and then we stop.

the number 4 can appear either in I throw, or II throw or .... indefinitely

So X = the no of throws can be from 1 to infinity

This is a discrete distribution countable.

Sample space= {1,2,.....}

b) Prob ( 4 never appears) = Prob (any other number appears in all throws)

= \frac{5}{6} *\frac{5}{6} *\frac{5}{6} *\frac{5}{6} *...\\=(\frac{5}{6} )^n

where n is the number of throws

As n tends to infinity, this becomes 0 because 5/6 is less than 1.

Hence this probability is approximately 0

Or definitely 4 will appear atleast once.

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If angle p is right angle and angle p and angle q are supplementary then what is angle q
Schach [20]
Right angle (angle p) = 90°
supplementary means total equals 180°
so 90° + q = 180°
subtract 90° from both sides
q = 90°
8 0
3 years ago
The weights of 40 students were recorded. If the 75th percentile of
RUDIKE [14]
In the given question, there are numerous information's already provided. It is important to note then down first. With the help of those given information's the required answer can be easily reached.
Percentage of students that weighed 140 pounds = 75 percent
Then
Percentage of students that weighed more than 140 pounds = (100 - 75) percent
                                                                                                  = 25 percent
Total number of students that were weighed = 40 students
Total number of students that weighed more than 140 pounds = (25/100) * 40
                                                                                                    = (40/4) students
                                                                                                    = 10 students
So the number of students that weighed more than 140 pounds is 10. So the correct option in regards to the given question is option "1".
7 0
3 years ago
How to find the minimum value of an expression
AURORKA [14]
Your answer is positive
8 0
3 years ago
Read 2 more answers
NEED HELP ASAP ILL GIVE 30 POINTS
Murljashka [212]

1) 1/2 * 1/2 = 1/4

2) 43/100 of mine were heads, and (.43)^2 = .1849

3) 1/2 * 1/2 = 1/4

4)57/100 of mine were tails, and (.57)^2 = .3249

5) 1/2 * 1/2 * 2 (multiply by 2 because order doesn't matter) = 1/2

6) .43 *.57 = .2451

7) There is probably a difference becasue there wasn't enough data. The more times you flip the coin, the closer you'd get to 1/2 head 1/2 tails (theoretically), but you can't flip a coin an infinite amount of times, so it (usually) will not give you an exact 1:1 ratio between heads and tails

4 0
3 years ago
Question 17
jeyben [28]

Answer:

Options C and D are the correct options.

Step-by-step explanation:

Option A

cos(H) = 0.3846

By applying cosine rule in ΔFGH,

cos(H) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{36}{39}

           = 0.9231

False

Option B

cos(G) = 0.9231

By applying cosine rule in ΔFGH,

cos(G) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{15}{39}

           = 0.3846

False

Option C

sinG = 0.9231

By applying sine rule in ΔFGH,

sin(G) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

          = \frac{36}{39}

          = 0.9231

True

Option D

tanG = 2.4

By applying tangent rule in ΔFGH,

tanG = \frac{\text{Opposite side}}{\text{Adjacent side}}

        = \frac{36}{15}

        = 2.4

True

Therefore, Options C and D are the correct options.

6 0
3 years ago
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