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3 years ago

Please help this is the last question on my test!! What is the approximate area of a circle with a radius of 4 feet? Use 3.14

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

4 0

Answer:

50 feet²

Step-by-step explanation:

r = 4 feet

Area of circle = $\pi$ r²

= 3.14 * 4 * 4

= 50.24 = 50 feet²

earnstyle [38]3 years ago

4 0

Answer:

50.24 square feet

Step-by-step explanation:

area = π $r^{2}$

area = 3.14 x 4ft

area = 50.24 $ft^{2}$

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How do you solve ? 2(x−(3+2x)+9)=3x−8

PIT_PIT [208]

Hey there!!

Given equation :

... 2 ( x - ( 3 + 2x ) + 9 ) = 3x - 8

Using the distributive property.

... 2 ( x - 3 - 2x + 9 ) = 3x - 8

... 2 ( -x + 6 ) = 3x - 8

Using the distributive property.

... -2x + 12 = 3x - 8

Subtracting 12 on both sides.

... -2x = 3x - 8 - 12

... -2x = 3x - 20

Subtracting 3x on both sides.

... -2x - 3x = -20

... -5x = -20

Dividing by -5 on both sides.

... x = -20 / -5

... x = 4

Hence, the answer is 4.

Hope my answer helps!

6 0

2 years ago

Question 2 of 30

Igoryamba

Answer:

f(x) is shifted 7 units to the right.

3 0

1 year ago

Read 2 more answers

Write an equation for a line that passes through (-4,8) and 8,-1

KatRina [158]

Slope is change in y over change in x.

Change in y is -9
Change in x is +12

So -9/12 or -2/3

Answer -2/3

5 0

3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

2 years ago

Pls helpppppppppppppppppppppp

Delvig [45]

Answer:

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Step-by-step explanation:

3 0

2 years ago