Suppose :
2^x = t ..**&**.. 3^y = u
_____________________________
t + u = 9 × 3 3t + 3u = 27
=====》
2t - 3u = 8 2t - 3u = 8
+ __________
5t = 35
5 × t = 5 × 7
t = 7
&
u = 2
________________________________
Thus :
2^x = 7 ===》 x = Log _ 2 { 7 }
3^y = 2 ===》 y = Log _ 3 { 2 }
:) Hope this answers your question :)
Answer:
Step-by-step explanation:
The intersection is when both functions have same coordinates
Substitute to get
- - 2x + 16 = 4x + 10
- 4x + 2x = 16 - 10
- 6x = 6
- x = 1
The y- coordinate is
- y = - 2(1) + 16 = -2 + 16 = 14
So the intersection point is (1, 14)
