800 is to the nearest hundred
Answer:
C. y₂ = (1 + (t/n))²
Step-by-step explanation:
yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)
yₙ₊₁ = yₙ + Δt yₙ
yₙ₊₁ = yₙ + (t/n) yₙ
When n=0:
y₁ = y₀ + (t/n) y₀
y₁ = 1 + (t/n)
When n=1:
y₂ = y₁ + (t/n) y₁
y₂ = 1 + (t/n) + (t/n) (1 + (t/n))
y₂ = 1 + (t/n) + (t/n) + (t/n)²
y₂ = 1 + 2(t/n) + (t/n)²
y₂ = (1 + (t/n))²
Answer:
x = 3/2 | y = -3
Step-by-step explanation:
Given equations:
- y = 2x - 6. . . .(i)
- y = -4x + 3. . . . (ii)
Substituting from equation (i) for y:
==> 2x - 6 = -4x + 3
==> 2x + 4x = 6 + 3
==> 6x = 9
<em>dividing both </em><em>sides by 3</em><em>:</em>
==> 2x = 3
==> x = 3/2
Substituting 3/2 for x in equation (i):
==> y = 2(3/2) - 6
==> y = 3 - 6
==> y = -3
18 (goes down): 17, 16, 15
12 (goes up): 13, 14, 15
The shortest height at which the two stacks of boxes will be the same height is 15.
Hope I was able to help!
