A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.
1/2 - y (6y - 8)
1/2 -6y2 - 8y
the answer is A
Answer:
x = -1 or 2
Step-by-step explanation:
Taking the antilog, you have the quadratic ...
x^2 -x -1 = 1
x^2 -x -2 = 0 . . . . subtract 1
(x -2)(x +1) = 0 . . . factor
The values of x that make these factors zero are the solutions to the equation.
x = 2 or x = -1