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olga55 [171]
3 years ago
11

boxes that are 12 inches tall are stacked next to boxes that are 18 inches tall. what is the shortest height as which the two st

acks will be the same height
Mathematics
1 answer:
olga55 [171]3 years ago
6 0
18 (goes down): 17, 16, 15
12 (goes up): 13, 14, 15

The shortest height at which the two stacks of boxes will be the same height is 15. 

Hope I was able to help!
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Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


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Answer:

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1st you have to subtract 7 form 301 so you get 294

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