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3 years ago

Which expressions are equivalent to 4(42)? Select each correct answer. A: 4(40 + 2) B: 4(4 + 2) C: 4(4 + 20) D: 4(20 + 22)

Mathematics

2 answers:

olga2289 [7]3 years ago

8 0

Answer A and D are equivalent to 4(42).

Amiraneli [1.4K]3 years ago

4 0

You do the math in the parenthesis first so for A 40 +2 = 42 becoming 4(42) and D 20 + 22 = 42 becoming 4(42)

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Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points

nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

$2(3x-1)+x\\Distribute\\6x-2+x\\7x-2$

For Problem 2, the work is as follows:

$(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5$

For Problem 3, the work is as follows:

$5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10$

For Problem 4, the work is as follows:

$4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1$

For Problem 5, the work is as follows:

$\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3$

For Problem 6, the work is as follows:

$17 *0.06 = 1.02\\17+1.02 = 18.02$

For Problem 7, the work is as follows:

$x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1$

For Problem 8, the work is as follows:

$y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1$

For Problem 9, the work is as follows:

$3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2$

For Problem 10, the work is as follows:

$(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5$

Hope this Helps!

4 0

3 years ago

I have no clue to what I even need to do.

Gre4nikov [31]

$\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}$

$\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r$

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3 years ago

Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.

Sedaia [141]

The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x.

3 0

3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$