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adoni [48]
3 years ago
9

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –(x – 6) and passes through

the point (−2, −2)? y = –x – y = –x + y = x – 1 y = x + 1
Mathematics
1 answer:
Mkey [24]3 years ago
4 0
Let's convert the equation in point-slope form to slope-intercept form.

y - 4 = -(x - 6)
Multiply everything out.
y - 4 = -x + 6
Add 4 to both sides.
y = -x + 10

To be perpendicular, the slope of the new has to be the reciprocal of the other line. To slope in this equation is -1/1. To get the reciprocal, flip the numerator and denominator and change the sign too.

-1/1 becomes 1/-1, and changes to 1/+1, or 1.

y = x + b

Input the coordinate point and solve for b.

-2 = -2 + b
Add 2 to both sides.
0 = b

y = x
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Write an equation of a line parallel to line GH below in slope-intercept form that passes through the point (-5, 6).
Alexandra [31]
There are several information's of immense importance already given in the question. Based on those information's. the answer can be easily deduced.

We already know that
y = mx + b
Then
Slope for GH = (6 - 2)/(- 2 - 2)
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We already know that parallel lines have the same slope
Then
<span>6 = -1(5) +b 
</span>6 = - 5 + b
b = 11
Then, the equation is 
y = x + 11
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the last option or the fourth option.
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finlep [7]

Answer:

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Mashutka [201]

Answer:

True

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