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3 years ago

How to write 8.571 in word form

Mathematics

2 answers:

vivado [14]3 years ago

8 0

Eight "and" five hundred seventy one.

iren [92.7K]3 years ago

6 0

8.571 in word form is:

Eight and five hundred seventy-one thousandths

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Use 2 as a factor to write an expression that is equivalent to the expression 8x+6y .

posledela

2(4x + 3y). You just factor out the two

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2 years ago

PLEASE HELP WILL GIVE BRAINLIIEST 20 POINTS 6TH GRADE ASAP PLEASE

nignag [31]

Answer:

Both A and B

Step-by-step explanation:

For functions you are just trying to make sure all the x's are different.

So let's look at A: The x's there are all different so it is a function

Now let's look at B: The x's there are all different so it is a function.

Both A and B

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3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

2 years ago

Read 2 more answers

Solve for x in the equation x² + 2x +1 = 17

SashulF [63]

x=3.18,x=-5.18
It have two answers

7 0

2 years ago

QUESTION 3 Find the interest. Round to the nearest cent. $1850 at 8% for 14 months

Genrish500 [490]

Answer:

$I=\$172.67$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=14/12\ years\\ P=\$1,850\\r=0.08$

substitute in the formula above

$I=1,850(0.08(14/12))$

$I=\$172.67$

3 0

2 years ago