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2 years ago

Colin walked a distance of 15 miles in 6 hours work out colins average speed

Mathematics

2 answers:

inna [77]2 years ago

5 0

Answer:

2.5 mph

Step-by-step explanation:

I just divided 15 by 6

KATRIN_1 [288]2 years ago

5 0

Answer:

Collins average speed was 2.5 mph because 15 / 6 = 2.5

Step-by-step explanation:

hope it helped

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You win an online auction for a toy. Your winning bid of $35 is 70% of your maximum bid. How much more were you willing to pay f

luda_lava [24]

35 = 70%

If you divide 35 by 7, you will find what 10% of your maximum bid is.
35/7 = 5
5 = 10%

Multiply your value of 10% by 10 to get 100%.
5*10 = 50

Your maximum bid would be $50. You actually spend $35. To find the amount more you were willing to pay, subtract the two values.
$50-$35 = $15

Answer: You were willing to pay 15 more dollars than you did.

5 0

3 years ago

A group of friends are at a baseball game and are purchasing souvenirs. Dustin purchased 5 t-shirts and 1 baseball cap, spending

Inessa [10]

Answer:

Shirt-$19

Cap-$24

Step-by-step explanation:

5s+1c=119

1s+1c=43

1c=43-1s

substitute:

5s+(43-1s)=119

5s+43-1s=119

4s=119-43

4s=76

1s=19

substitute:

1c=43-(19)

1c=24

7 0

3 years ago

Calculate 3217. km + 13.1 km + 1.30 km. round off if necessary to apply the rule of significant figures for addition and subtrac

QveST [7]

3217 + 13.1 + 1.3 can also be written as

3217.0
+ 13.1
1.3
----------
3231.4

Your final answer should be 3231.4 or option 4. Hope this helps!

6 0

3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

2 years ago

Read 2 more answers

Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

5 0

2 years ago