Answer:
The smallest of the two consecutive integers is 10 or less.
Step-by-step explanation:
Let x represent the smallest of the even integers in the sequence.
Then the sum of two consecutive even integers is ...
x + (x +2) = 2x +2
And half the sum of the next two consecutive even integers is ...
(1/2)((x +4) + (x +6)) = x + 5
The relationship between these values is ...
2x +2 ≤ 7 + (x +5)
Subtracting x+2 gives ...
x ≤ 10
The least of the two consecutive even integers is at most 10.
1/5, .35, 12/25, .50, 4/5
If you want the line to be perpendicular to the given line, you would have to keep the same slope and change the B-value.
Hope this Helps!<3
Answer:
you have a 7/12 chance
Step-by-step explanation:
The sample space has 12 elements:
T1, T2, T3, T4, T5, T6
H1, H2, H3, H4, H5, H6
(From a combinatorics perspective, there are 2 options for the coin and 6 for the die for a total of 2 * 6 = 12.)
There are 6 heads results and one tales result that has a 4 for a total of 7 possibilities that meet your criteria. That makes the probability 7 / 12.
here is the link for where i got my answer https://www.quora.com/If-you-flip-a-coin-and-roll-a-die-what-is-the-probability-the-coin-lands-heads-up-or-the-die-lands-showing-the-number-4
