Subtract exponents, divide coefficients
39/13t^7u^-6v-2
Answer:
These lines are perpendicular.
Step-by-step explanation:
Put both equations in the slope intercept form of a line.
y = -6x - 8 This is already in the slope intercept form for a line
-x + 6y = 12 Add x to both sides of the equation
6y = x + 12 Divide through the whole equation by 6
y = 1/6x +2
Now we compare the two slopes of -6 and 1/6. They are negative reciprocals of each other. That means that the line are perpendicular.
Y = -6x - 15
We’re already at -3 (y) and the slope is negative so the y intercept is < -3. X is -2 and we need to find the y when x is 0. -2 is 2 away from 0 and 6 (the slope) times 2 is 12. -3 - 12 = - 15
