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S_A_V [24]
3 years ago
11

HELP I NEED HELP SETTING THIS UP

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0

Answers:

The starting equation is (x+5)/3 = 7 which can be written as \frac{x+5}{3} = 7

The solution to this equation is x = 16

========================================================

Explanation:

Let x be a placeholder for some number. If we start off with some number and add on 5, then we go from x to x+5. The next thing we do is divide all of "x+5" all over 3 to get (x+5)/3 which can be written as \frac{x+5}{3}. I'll use the first style of notation.

Set the expression (x+5)/3 equal to 7 and that leads us to the equation:

(x+5)/3 = 7

so this is the first part of the answer. Now onto the second part which is solving for x. We want to get x all by itself on its own side.

To do this, we follow the order of operations PEMDAS in reverse. So we undo division first by multiplying both sides by 3. Then we undo the addition of 5 by subtracting 5 from both sides

(x+5)/3 = 7

3*(x+5)/3 = 3*7 ...... multiply both sides by 3

x+5 = 21

x+5 - 5 = 21 - 5 ..... subtract 5 from both sides

x = 16

So the unknown mystery number is 16. As a check, note how adding 5 to 16 gets us 16+5 = 21, which if we divide by 3 we end up with 21/3 = 7 which is what we want. So the answer is confirmed.

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3 years ago
What is RS? Please help will give Brainlyest.
IceJOKER [234]

Answer:

<h2>         RS = 47</h2>

Step-by-step explanation:

RV=VU and SW=WT    ⇒    VW=\dfrac{RS+UT}{2}

Therefore:

3x+5=\dfrac{2x+15+6x-37}{2}\\\\3x+5=\dfrac{8x-22}{2}

3x + 5 = 4x - 11        {subtract 5 from both sides)

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3 0
3 years ago
Kate and David each have $10. Together they flip a coin 5 times. Every time the coin lands on heads, Kate gives David $1. Every
olga55 [171]

Answer:

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hope this was helpful

8 0
3 years ago
7. This year, the water in a reservoir dropped by 60%. For the original water level to be restored next year, by what percent mu
ale4655 [162]

Answer:

Given: Water in a reservoir dropped by 60%

Step-by-step explanation:

let the total water level of reservoir be 100.

then, in first year

the water reservoir dropped = 60% of 100

                                               =\frac{60}{100} * 100

                                               = 60

therefore, total water level needed to be restored till next year= 100

remaining water level to restore till next year= 100-60

                                                                           =40

                                                       percentage= \frac{40}{100} * 100

                                                                         =40%

                     

8 0
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