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kondaur [170]
3 years ago
14

Find the Circumference and area of the circle with the center C=(-1,2) and a point on the circle A(4,-1). Round to the nearest t

enth.
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

idk the answer but i do know this

Step-by-step explanation:

the formula for the area of a circle is pi times the radius squared

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HEEEEEEELLLPPPPPPPPP!!!!! PLEASEEEEEEEE
Klio2033 [76]

Answer:

a) a_n=2(a_{n-1}), where a_1=5.

b)  a_n=5(2)^{n-1}

Step-by-step explanation:

The given sequence is


5,10,20,40....


The first term of the sequence is

a_1=5


The second term is a_2=10


The common ratio for this sequence can be determined using any two consecutive terms in the sequence.

Using the first two terms, the common ratio is

r=\frac{a_2}{a_1}


\Rightarrow r=\frac{10}{5}=2


a) The recursive rule is given by,


a_n=r(a_{n-1})


a_n=2(a_{n-1}), where a_1=5.


b) The explicit rule is given by a_n=a_1r^{n-1}


\Rightarrow a_n=5(2)^{n-1}





3 0
2 years ago
What is the sum of f and 6
Inga [223]
The sum of f and 6 is simply f+6.
It is like this because f is a variable and we do not know its value.
8 0
3 years ago
Read 2 more answers
The line that passes through the point (-4, 2) and has a
xxMikexx [17]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

3 0
2 years ago
2) What is the slope of a line perpendicular to the line y = 2x – 3 ?
-BARSIC- [3]

Answer:

The correct answer is c.

7 0
3 years ago
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Write expression using a positive exponent<br />
GrogVix [38]

a^{-n}=\dfrac{1}{a^n}\\\\4^{-1}=\dfrac{1}{4}\\\\5^{-3}=\dfrac{1}{5^3}\\\\-6^{-2}=-\dfrac{1}{6^2}\\\\-3^{-3}=-\dfrac{1}{3^3}\\\\3^{-5}=\dfrac{1}{3^5}\\\\10^{-4}=\dfrac{1}{10^4}\\\\p^{-1}=\dfrac{1}{p^1}\\\\a^{-10}=\dfrac{1}{a^{10}}\\\\d^{-3}=\dfrac{1}{d^3}\\\\q^{-4}=\dfrac{1}{q^4}\\\\b^{-15}=\dfrac{1}{b^{15}}\\\\r^{-20}=\dfrac{1}{r^{20}}

4 0
3 years ago
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