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andre [41]
4 years ago
11

He legs of an isosceles triangle have lengths x + 1 and -x + 7 . The base has length 3x - 3. What is the length of the base?

Mathematics
1 answer:
marishachu [46]4 years ago
3 0

x + 1 =   - x + 7
= 6
6 = 3(x) - 3
6 + 3 = 3x
9 = 3x
x = 3
base is c. 3
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\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

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One might just as well come along and post:

         <em>"Answer the following question, using the following words." </em>

and then leave it at that, for others to puzzle over.


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