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Pavlova-9 [17]
3 years ago
5

Plz awnser quick!!! It's almost tomorrow need to know the fraction and decimal to 1-4!!!! Plz quick plzzz I'll give u 30 points!

!

Mathematics
1 answer:
morpeh [17]3 years ago
6 0
Edit: 1. 2 2/5 2. 2 4/5 3. 3 4/5 4. 3 1/2
You might be interested in
Suppose a random sample of n measurements is selected from a binomial population with probability of success p = .39. Given n =
Oksi-84 [34.3K]

Answer:

The answer is below

Step-by-step explanation:

a) Given that the number of sample (n) = 300, therefore since n > 30, the distribution of the sample means is going to be normally distributed.

b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.

\mu_x=\mu=np=300*0.39=117

c) The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:

\sigma_x=\sqrt{np(1-p)} =\sqrt{300*0.39(1-0.39)} =8.44

8 0
3 years ago
In a sequnece u5=-3.7 and u15 =-52.3, what is the 19th term
PilotLPTM [1.2K]

u19=-71.74

Step-by-step explanation:

u5=a+4d=-3.7....(1)

u15=a+14d=-52.3....(2)

-10d=48.6

d=-48.6/-10

d=-4.86

Substitute-4.86 into....(1)

u5=a+4(-4.86)=-3.7

a+(-19.44)=-4.7

a=-3.7-(-19.44)

a=15.74

19term=a+18d=?

=15.74+18(-4.86)

=15.74+(-87.48)

19th term =-71.74

6 0
2 years ago
Find the maximum profit and the number of units that must be produced and sold in order to yield the maximum profit. Assume that
V125BC [204]

Answer:

-1.39

Step-by-step explanation:

Revenue and cost as a function of units sold are u(x) = 9x-2x^{2}andc(x)=x^{3}-3x^{2}+4x+1  respectively.

we are have to know for which value or input units are these functions at maximum which translates to for how many units is the revenue maximum and for how many same units is our cost minimum.

5 0
3 years ago
Divide 29 into two parts so that the sun of the squares of the parts is 425.Find the value of each Part.
Taya2010 [7]

Answer:

13 and 16

Step-by-step explanation:

let the 2 parts be x and y, then

x + y = 29 → (1) and

x² + y² = 425 → (2)

From (1) → x = 29 - y → (3)

substitute x = 29 - y into (2)

(29 - y)² + y² = 425 ( expand factor )

841 - 58y + y² + y² = 425 ( rearrange into standard form )

2y² - 58y + 416 = 0 ← in standard quadratic form

divide all terms by 2

y² - 29y + 208 = 0

Consider the factors of 208 which sum to - 29

These are - 13 and - 16, hence

(y - 13)(y - 16) = 0

equate each factor to zero and solve for y

y - 13 = 0 ⇒ y = 13

y - 16 = 0 ⇒ y = 16

substitute these values into (3)

x = 29 - 13 = 16 and x = 29 - 16 = 13

The 2 parts are 13 and 16


4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!
katovenus [111]
Let me ask my brother he's smart
5 0
3 years ago
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