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2 years ago

Angles L and M are supplementary. If m ∠ L = (x+2)° and m ∠ M = (x-6)°. What is the value of x?

Mathematics

1 answer:

marta [7]2 years ago

7 0

The value of X is 92.

please see the attached picture for full solution

Hope it helps

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Find the slope of the line represented by the table of values

Leya [2.2K]

Answer:

-5/3

Step-by-step explanation:

To solve for slope we use the slope formula which is y2-y1/x2-x1.

For this problem I chose the points: (-5,10) and (-2,5)

-5 is x1, 10 is y1, -2 is x2 and 5 is y2

We now plug in the points into the slope formula:

5-10/-2-(-5)= -5/3

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2 years ago

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What is the degree of -8mn^2

jek_recluse [69]

Answer: 2

Step-by-step explanation:

To find the degree, use the exponent. An exponent of two means a degree of two, like an exponent of four means a degree of four

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2 years ago

you have been asked to build a scale model of your school out of toothpicks . Imagine your school is 30ft tall . your scale is 1

zmey [24]

1.26cm/1ft * 30ft = 37.8cm
37.8cm/6.3cm=6
Your model would be six toothpicks tall.

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3 years ago

Eric made a scale drawing of the auditorium. The stage, which 15 35 feet wide in real life,

Molodets [167]

Based on the given conditions, formulate: 5/35
Simplify by dividing by dividing the numerator and denominator by 5: 1/7

Therefore the scale of the drawing is 1/7

7 0

1 year ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago