All categories

3 years ago

A like goes through the point (-4,-6) and the point (10,1) write the equation of the line intercept form

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Answer:

I IM NOT 100 PERCENT BUT IT MIGHT BE A

Step-by-step explanation:

i think it might be B

because first, u do slope formula y2-y1 and x2-x1 so 1-(-6) and 10-1

then u get 7/14 which is 2 and then plug in the numbers like -4=2(-6)+b

and then you add 12 to -4 and get 8=b I think after this u divide and get 4

You might be interested in

Does someone know tha answer??

e-lub [12.9K]

Answer:

either 5 or 6 months

Step-by-step explanation:

Tom M Jerry

500 1 125

475 2 175

450 3 225

425 4 275

400 5 325

375 6 375

3 0

3 years ago

Three hundred seventeen kids went on a field trip last

arlik [135]

Answer:

310 kids/ 6 busses

310/6=51.6 so

52 or 51 kids on each bus.

3 0

3 years ago

Read 2 more answers

To find the range you take the big number and subtract the small number.True False

statuscvo [17]

Answer:

True

Please give Brainliest

7 0

3 years ago

Two lines are intersecting. What is the value of x? Enter your answer in the box. (x + 23) (2x + 4)° Help! Please!!!

Delicious77 [7]

Answer:

$x = 51^o$

Step-by-step explanation:

Given

Intersecting lines

Required

Find x

To do this, we make use of:

$x + 23^o + 2x + 4^o = 180^o$ --- angle on a straight line

Collect like terms

$x + 2x = 180^o - 4^o - 23^o$

$3x = 153^o$

Divide both sides by 3

$x = 51^o$

5 0

3 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

3 years ago