Answer:
9.1 feet
Step-by-step explanation:
Please refer to the image attached for explanations
Given:
The graph of a downward parabola.
To find:
The domain and range of the graph.
Solution:
Domain is the set of x-values or input values and range is the set of y-values or output values.
The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.
Domain = R
Domain = (-∞,∞)
The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.
From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.
Range = All real numbers less than or equal to -4.
Range = (-∞,-4]
Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].
When you compare two functions f(x) and g(x), you're looking for a special input 
such that
Since you have the table with some possible candidates for , you simply have to choose the row that gives values for f(x) and g(x) that are as close as possible (the exact solution would give the same value for f(x) and g(x), so the approximate solution will give values for f(x) and g(x) that are close to each other).
In your table, the values for f(x) and g(x) are closer when x=-0.75
Answer:
See attachment for plot
Step-by-step explanation:
Given
--- increment in the rate
First, we need to model the new rate
A linear equation is:
Where
Compare and . we have:
The above represents the previous rate.
The new rate:
Rewrite as:
So, the model is:
<u>The plot at 1 and 2 minutes</u>
When 
When 
So, we have:
<em>Whether she moves backwards or forward, the distance covered remains the same</em>
<em>See attachment for plot</em>
First question:
1. Set equations equal to each other so 5x-9=2x+6
2. Put x's on one side so that 3x=15
3. Divide by 3 so that x=15
4. Substitute 15 in for x so that y=2(15)+6
5. Solve for y so that y=36
6. Thus the equations intersect at (15,36)
Second question:
1. Since for lines y=mx+b, and m=slope=3 you only need to write an equation with slope 3
2. y=3x+b, b can be any number
