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RSB [31]
3 years ago
6

Alex worked 45.75 hours this week at $7.86 per hour. What is his gross pay?

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0
45.75h(7.86d/h)=$359.595

Which is $359.60 to nearest cent.
Len [333]3 years ago
3 0
All you really need to do is multiply

$45.75 * $7.86 = $359.60

Alex's gross pay Is - $359.60

Hope I helped ( Smiles )

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b=2a/h

Step-by-step explanation:

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For radians, multiply the number of jump revolutions by 2 pi 

<span>For degrees, multiply the number of revolutions by 360

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13 squared? how does it mean and what is the solution?
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13 squered it means that =13 to the second power
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What is N in 25-n=32?
Lostsunrise [7]
Simplify both sides of the equation.

<span><span>25−n</span>=32

</span><span>Simplify:

</span><span><span><span>−n</span>+25</span>=32

</span>Subtract 25 from both sides.

<span><span><span><span>−n</span>+25</span>−25</span>=<span>32−25

</span></span><span><span>−n</span>=7

</span>Divide both sides by -1.

<span><span><span>−n/</span><span>−1 </span></span>= <span>7/<span>−1

</span></span></span><span>n=<span>−7

</span></span>Ans:
<span>n = <span>−7</span></span><span>
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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
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\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
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