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Answer:
The genotype frequency refers to the percentage of individuals in a population with that genotype.
For example, of the frequency of genotype CC is 0.01, that is, 1 percent of the population has the genotype CC.
The total population size is 110.
Thus, the number of dogs with genotype CC would be = 0.01 of 110 ≈ 1
Similarly, number of dogs with genotype Cc would be = 0.18 of 110 ≈ 20
The number of dogs with genotype cc would be = 081 of 110 ≈ 89
Answer:
C
Explanation:
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Answer:
The correct answer will be option-C
Explanation:
The CsCl gradient centrifugation in Meselson Stahl experiments is done to separate the bands of the DNA containing isotopes on the basis of difference in the density.
In the experiment, bacterial cultures were grown in the medium of 15N and 14N but if we repeat the experiment with P32 and P31 instead of 15N and 14N and centrifugation is performed then the banding pattern will be the same as of the previous experiment as the method of the replication is same that is semi-conservative.
Thus, Option-C is the correct answer.
