Answer: L = 29cm
Step-by-step explanation:
Let's go!!
To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.
So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.
Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90
Then, you might to solve this system of equation:
2L + 2w = 90
w = L - 13
Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).
Our new system:
L + w = 45
w = L - 13
Using the substituition method:
L + L - 13 = 45
2L = 58
L = 29 cm
the width is 29 - 13 = 16 cm
Option B:
The perimeter of ΔABC is 28 units.
Solution:
AD = 5, DC = 6 and AB = 8
AD and AE are tangents to a circle from an external point A.
BE and BF are tangents to a circle from an external point B.
CD and CF are tangents to a circle from an external point C.
<em>Tangents drawn from an external point to a circle are equal in length.</em>
⇒ AD = AE, BE = BF and CD = CF
AE = 5
AE + BE = AB
5 + BE = 8
Subtract 5 from both sides.
BE = 3
BE = BF
⇒ BF = 3
CD = CF
⇒ CF = 6
Perimeter of the polygon = AE + BE + BF + CF + CD + AD
= 5 + 3 + 3 + 6 + 6 + 5
= 28
The perimeter of ΔABC is 28 units.
Option B is the correct answer.
47 times 22 = 1034
1034/2 = 517
380 is less than 517 so Renee has more than enough for each student.
^3/1331 = 11
11 x 11 x 11 = 1331
