Look at the picture below.
I hope this helps!
The range would consist of all real numbers EXCEPT for zero
Strategy A, drawing a diagram is the best strategy to solve this problem
a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
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