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3 years ago

Find the length of a rectangle if its

Mathematics

1 answer:

Alina [70]3 years ago

4 0

Answer: L = 29cm

Step-by-step explanation:

Let's go!!

To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.

So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.

Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90

Then, you might to solve this system of equation:

2L + 2w = 90

w = L - 13

Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).

Our new system:

L + w = 45

w = L - 13

Using the substituition method:

L + L - 13 = 45

2L = 58

L = 29 cm

the width is 29 - 13 = 16 cm

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SU and VT are chords that intersect at point R.

vovikov84 [41]

Answer:

<h2>The length of the line segment VT is 13 units.</h2>

Step-by-step explanation:

We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

$\frac{RS}{RT} =\frac{RV}{RU}$

Where

$RS=SR=x+6\\RT=x+4\\VR=RV=x+1\\RU=x$

Replacing all these expressions, we have

$\frac{x+6}{x+4} =\frac{x+1}{x}$

Solving for $x$ , we have

$x(x+6)=(x+4)(x+1)\\x^{2} +6x=x^{2} +x+4x+4\\6x-5x=4\\x=4$

Now, notice that chord VT is form by the sum of RT and RV, so

$VT=VR+RT\\VT=x+1+x+4\\VT=2x+5$

Replacing the value of the variable

$VT=2(4)+5\\VT=8+5\\VT=13$

Therefore, the length of the line segment VT is 13 units.

5 0

3 years ago

Read 2 more answers

HELP I WILL MAEK BEAINLIST PLEASE

wolverine [178]

Answer:

260,548668 or 260.55 round to the nearest hundreds

Step-by-step explanation:

Area of the trapezoid:

[(major base + minor base)x height]/2

[(22 + 12) x 12]/2 = 204 cm^2

radius = diameter / 2 = 12 / 2 = 6 cm

Area of a semicircle

(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2

total area = 204 + 56,548668 = 260,548668 cm^2

6 0

3 years ago

The function f ( x ) = 2 ⋅ 5 ^x can be used to represent an exponential growth curve. Which of the following points is NOT on th

12345 [234]

Answer:

Point (2, 20) does not lie on the given curve.

Step-by-step explanation:

Let us see explanation:

$f(x) = 2. \: {5}^{x} \\ \\ \therefore \: f(x) \: at \: x = 2 \\ f(2) = 2. {5}^{2} = 2.25 = 50 \\ \\ hence \: at \: x = 2 \: \: f(x) = 50 \\ \therefore \:point (2 \: \: 20) \: does \: not \: lie \: on \: the \: \\ \: \: \: \: \: curve.$

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3 years ago

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Divide fractions: 5/6 divided by 6/10 (leave as improper fraction if necessary)

tankabanditka [31]

Answer:

25/18

Step-by-step explanation:

5/6 / 6/10

K C F

5/6 * 10/6

50/36 = 25/18

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3 years ago

10 times as many as blank tens is 30 tens

yKpoI14uk [10]

The answer to that question will be 3

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3 years ago