3.5r.....................
Answer:
Step-by-step explanation:
6-4[x+1-(y+3)]+6y
6-4[x+1-y-3]+6y
6-4[x-2-y]+6y
6-4x+8+4y+6y
14-4x+10y
The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).
<h3>What is the factored form of an equation that has the zeros or roots 4 and -7?</h3>
Roots are simply the points where the graph intercepts with the x-axis. ( y = 0 )
That is, y = 0 the roots
Given the roots of the equation;
Now, at x = 4,
x = 4
x - 4 = 0
y = ( x - 4)
Also, at x = -7,
x = -7
x - ( - 7 ) = 0
x + 7 = 0
y = ( x + 7 )
Hence; for the equation with the given roots; 4 and -7 will be;
y = ( x - 4)( x + 7 ).
The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).
Learn more about roots of quadratic equation here: brainly.com/question/26926523
#SPJ1
Answer:
f(-2) = 1/9
Step-by-step explanation:
Plug in -2 to x in the equation:
f(x) = 3^x
f(-2) = 3^(-2)
Solve. Note that if there is a negative in the power, you must flip the "fraction" and set it over 1. The answer itself does not become negative:
f(-2) = 1/(3^2)
f(-2) = 1/(9)
f(-2) = 1/9 is your answer.
~
