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2 years ago

Which one of the following is NOT true about the expression shown

Mathematics

1 answer:

garri49 [273]2 years ago

7 0

Answer:

A) The expression is a trinomial.

Step-by-step explanation:

If the degree is 2, the expression would be a binomial, not a trinomial. If this answer is correct, please make me Brainliest!

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Pls help I need a good grade Show your work

lesya [120]

Answer:

14 weeks

Step-by-step explanation:

500 - 220 = 280

280 / 20 = 14

4 0

2 years ago

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Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

2 years ago

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Channing bought a new bike that retails for $299. If the store is currently

Alenkinab [10]

it should be 271.94

3 0

3 years ago

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PLEASE HELP I WILL BRAINLIEST !

jasenka [17]

Answer:

10 1/12

Step-by-step explanation:

In order to subtract fractions, you have to give them a common denominator.

18 1/2 can be rewritten as 18 6/12, as they are the same thing and 6/12 simplifies to 1/2. We make it 6/12 because we have to subtract it by 8 5/12, and the denominators are both 12.

So now we have 18 6/12 - 8 5/12, which gives us 10 1/12.

8 0

2 years ago

What is the range of the function f(x)= -2x-4 when the domain is {-3,-2,-1}?

Paha777 [63]

F(-3)=(-2)*(-3)-4=6-4=2

F(-2)=(-2)*(-2)-4=4-4=0

F(-1)=(-2)*(-1)-4=2-4=-2

6 0

3 years ago